Consider c as the cost of the widget so that our given equation is
c = 0.1w^2 + 20w
Take the derivate of the equation.
d/dt (c = 0.1w^2 + 20w)
dc/dt = 0.2w + 20
Given dc/dt = $16000 per month, the number of widgets would contain:
16000 = 0.2w + 20
-0.2w = 20 - 16000
-0.2w = -15980
w = 79900 widgets
Answer:
D
Step-by-step explanation:
Answer:
Part 3: 9 Dogs
Step-by-step explanation:
It says that the ratio they want you to put it in is dogs/students, so dogs are x, and students are y, so if there are 4 students for every dog, 36 students would require 9 dogs
And if the roles were switched it would be students x, dogs y, and there would be 9 students for 36 dogs :D
Answer:
Option b
Step-by-step explanation:
- Calcium has atomic no-20
- Hence it has 20 protons
- Silicon has atomic no 14
- Hence it has 14protons
Total:-

627.0m the process is shown in the following picture.