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2 years ago

Hheellpp mmee pplleeaassee

Mathematics

2 answers:

STALIN [3.7K]2 years ago

8 0

Answer:

3+105

Step-by-step explanation: Im so sorry if its wrong

alekssr [168]2 years ago

6 0

Answer:

Simplified Expression: 3d + 105

Step-by-step explanation:

You have to distribute the number outside the parenthesis (3) to the number(s) inside the parenthesis (d + 35).

You can rewrite it like this: (3)(d) + (3)(35)

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A chestnut falls out of a tree 45 feet above the ground. Use the vertical motion model, H=-16t^2+vt+s s to find how long it take

valentinak56 [21]

Answer:

1.7 seconds

Step-by-step explanation:

we have

$H=-16t^2+vt+s$

where

v is the initial velocity (in feet per second)

s represents the initial height (in feet)

In this problem we have

$v=0$ ---> because the object is dropped

$s=45\ ft$

substitute

$H=-16t^2+45$

Remember that

When the chestnut hit the ground the value of H is equal to zero

For H=0

$-16t^2+45=0$

solve for t

$16t^2=45\\t^2=2.8125\\t=\pm1.7\ sec$

therefore

The solution is t=1.7 sec

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2 years ago

Write a linear equation for the graph in point-slope form. Show your work. (2 points) (PLEASE HELP)

Wittaler [7]

Answer:

We need to see the graph to answer this question

4 0

2 years ago

Read 2 more answers

To help you just Incase you need it

Lerok [7]

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5 0

3 years ago

the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

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3 years ago

IXL Q.12 PLS HELP I HAVE BEEN STUCK ON THIS ONE FOR SOME TIME.

Furkat [3]

Answer:

m∠1 = 100°

Step-by-step explanation:

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2 years ago