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sukhopar [10]
4 years ago
5

Suppose that a pattern repeats the sequence 2,4, 8, 7 over and over . Enter the first 11 terms of the pattern in the table below

term
Mathematics
2 answers:
lord [1]4 years ago
7 0
2,4,8,7,9,13,12,14,18,17,19,23,22,24,28,27
VLD [36.1K]4 years ago
4 0

Answer: 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5

Step-by-step explanation:

We know that the repeated patern is:

2, 4, 8, 7

Now, let's analyze the pattern:

2 + 2 = 4

so after 2 comes 4

4 + 4 = 8

and after 4 comes 8, so this metod has sense.

8 + 8 = 16

but after 8 comes 7, but you can see that 8 + 8 = 16, and 1 +6 = 7, so we now have a system to find the 11 first terms, if the addition of the previous number is a one digit number, then that is the therm, if the addition of the previous term is a two digit number, we need to add up the digits and that will be the term.

2

2 + 2 = 4

4 + 4 = 8

8 + 8 = 16, 1 + 6 = 7

7 + 7 = 14. 1 + 4 = 5

5 + 5 = 10. 1 + 0 = 1

1 + 1 = 2

2 + 2 = 4

4 + 4 = 8

and is easy to see that the pattern repeats:

so the first 11 terms are: 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5

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