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vodomira [7]
2 years ago
5

Juanita did this work to solve an equation. Did she make an error?

Mathematics
2 answers:
Sergio [31]2 years ago
6 0
Yes it should be a negative nine not a positive nine

Have a nice day : )
sashaice [31]2 years ago
6 0

Answer:

B

Step-by-step explanation:

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Jose wants to rewrite 24+9 using the greatest common factor and the distributive property. Which expression should he write?
Reil [10]
First get the factors of 24: 2*2*2*3Then the factors of 9: 3*3 Comparing the factors, the GCF is 3 Then you can rewrite the expression: 3*8 + 3*3 At this point, I'm not sure whether what you mean is really distributive property or not since this case is more of a factoring. 3*(8+3)
4 0
3 years ago
What is the following quotient?
almond37 [142]

Answer:

B)  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2

Step-by-step explanation:

Step 1: First we have to get rid off the roots in the denominator.

To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.

The conjugate of √5 + √3 is √5 - √3.

Now multiply given expression with √5 - √3

(√6 + √11)     (√5 - √3)

------------- x   -----------

(√5 + √3)        (√5 - √3)

Step 2: Multiply the numerators and the denominators.

√6√5 - √6√3 +√11√5 -√11√3

------------------------------------------

(√5)^2 - (√3)^2

Now let's simplify to get the answer.

√30-√18 +√55 - √33

-----------------------------

5 - 3

= √30 -3√2 +√55                                     [√18 = √9√2 = 3√2]

--------------------------

2      

The answer is  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2


Thank you.

4 0
2 years ago
Read 2 more answers
Which values are in the solution set of 111 = z^2 + 11 if the replacement set is {10, 12, 14, 16, 18}?
pantera1 [17]

Answer:

10

Step-by-step explanation:

Z ^2+11=111

Z ^2=100

Z=10

8 0
2 years ago
There are four roads from A to B and five roads from B to C. In how mamy different ways can a person travel from A to C?
Lelu [443]

That would be 4 * 5 = 20 ways  answer.

3 0
3 years ago
Read 2 more answers
How do you estimate? I don't really understand because for one question my teacher said you wouldn't round your numbers, but for
uranmaximum [27]

Answer:

You can round up to tenths, hundredths, thousandths, or tens, hundreds, and thousands. Some numbers, they have remainders when divided, so you would round them up to make them whole numbers or non-repeating decimals.

Hope this helps!!

Let me know if you need more information...

Step-by-step explanation:

4 0
2 years ago
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