This is a nice "rates of change" problem from Calculus.
Let the length and width of the rect. be L and W. We are given the following info:
dL/dt = 6 cm/s; dW/dt = 4 cm/s; L = 11 cm and W = 5 cm.
The area of the rect. is A = L*W. Differentiating,
dA/dt = L(dW/dt) + W(dL/dt).
Subst. the given info: dA/dt = (11 cm)(4 cm/sec) + (5 cm)(6 cm/sec).
Just evaluate this to find dA/dt: (44 + 30) cm^2/sec = 76 cm^2/sec
Answer:
1/8 of the original sum still remains.
Step-by-step explanation:
If you spend 3/4 of what you have, you have 1/4 left.
Now you spend 1/2 of that 1/4, so basically divide 1/4 by 2. When dividing fractions you can multiply the fraction by the reciprocal of the other fraction.
÷ = *
= 1/8
So I think 1/8 of the original sum still remains.
Hope this helped, please mark brainliest if possible. Have a nice day.
The most profitable investment for a candy shop that earns $1 profit per pound of candy is "Machine with $8 per hour operating cost, producing 14 pounds of candy per hour".<span>
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Answer:
b
Step-by-step explanation:
The answer is c. You double the number for finding radius