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Oliga [24]
3 years ago
11

Can some one please help me on math​

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

your answer is D

Step-by-step explanation:

\frac{3}{4} x-8=5.5

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Yolanda makes $11.25 per hour at her part-time job. During one week, she worked 12 2/5 hours and also earned some tips. Her fina
Delicious77 [7]

Answer:

She earned $20 in tips.

Step-by-step explanation:

First, you need to work out how much pay she'd get for 12 hours work:

12 x $11.25 = $135 for 12 hours work

Then, find out 2/5 of $11.25 to find out how much she would get for the 2/5 of an hour she worked:

2/5 of $11.25 = $4.50

Add both these sums together to get her total pay for hours worked:

$135 + $4.50 = $139.50

Subtract that sum from her total pay to find out how much money she earned in tips:

$159.50 - $139.50 = <u>$20</u>

7 0
3 years ago
Read 2 more answers
Greater than or less than the base?
yarga [219]

Answer:

I think grater then?

Step-by-step explanation:

4 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
What are the possible values for x in the equation 4x^2=64
Degger [83]

                                  <u> 4 x²  =  64</u>

Divide each side by  4 :     x² = 16

Take the square root
of each side:                     x = √16

                                   x = <em>+ 4</em>
and
                                   x = <em>- 4</em> .


4 0
3 years ago
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What values of a, b, and c would you use in the quadratic formula for the following equation? 6x^2+5x-4=0
Yanka [14]
So remember that in a quadratic equation there is a type of quadratic equation of the form ax^2+bx+c=0 so to find what values of a, b, and c you need for the quadratic formula, you need to look at your equation and label a, b, and c. In this equation a=6, b=5 and c=-4. So for the quadratic formula you would use a=6, b=5 and C=-4. I hope this helps!!!!!

5 0
3 years ago
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