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lora16 [44]
3 years ago
5

Five students wrote a mathematics test. The average mark was 68. If the marks for four of the students were 75, 62, 84 and 53, t

he mark of the fifth student was
Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:

66

Step-by-step explanation:

Use the formula for the mean of a set of numbers:

                  sum of the numbers

average = --------------------------------

                     count of numbers

Here we know that the average mark was 68, so we can write:

               

                           75 + 62 + 84 + 53 + x

average = 68 = ----------------------------------

                                           5

or                            274 + x

                  68 = -------------------

                                    5

Solving for x, we multiply both sides by 5:     340 = 274 + x.

Subtracting 274 from both sides effectively isolates x:

 340 = 274 + x

- 274    -274

------------------------

  66      =    x

The fifth student's mark was 66.

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given data:

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= 5/15 * 4/14

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= 0.0952 * 100

the probability that the two cards dealt to Anika would be diamond is 9.52% ~ 10%

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Tom decides to paint one wall in his room green. Use the dimensions below to calculate the area of the this wall.
Anton [14]

Option C:

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Solution:

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Width of the wall = 7 \frac{3}{4} feet

Area of the wall = length × width

                          $=12 \frac{1}{4}\times 7 \frac{3}{4}  

Convert mixed fraction into improper fraction.

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Convert improper fraction into mixed fraction.

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7 0
3 years ago
Paws at play made a total of $1234 grooming 22 dogs. Paws at Play charges $43 to groom each small dog and $75 for each large dog
vitfil [10]

Answer:

<u>Answer (a):</u>

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<u>Answer (b)</u>

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Step-by-step explanation:

Paws at Play made a total of $1234 grooming 22 dogs.

Paws at Play charges $43 to groom each small dog and;

$75 for each large dog.

Let the number of small dogs be 's'

And the number of large dogs be 'l'

<u>A system of equations will be:</u>

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;

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Subtracting (i) from (ii) we get;

32l = 288 , l = \frac{288}{32} = 9

So there are 9 large dogs.

8 0
3 years ago
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