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lora16 [44]
3 years ago
5

Five students wrote a mathematics test. The average mark was 68. If the marks for four of the students were 75, 62, 84 and 53, t

he mark of the fifth student was
Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:

66

Step-by-step explanation:

Use the formula for the mean of a set of numbers:

                  sum of the numbers

average = --------------------------------

                     count of numbers

Here we know that the average mark was 68, so we can write:

               

                           75 + 62 + 84 + 53 + x

average = 68 = ----------------------------------

                                           5

or                            274 + x

                  68 = -------------------

                                    5

Solving for x, we multiply both sides by 5:     340 = 274 + x.

Subtracting 274 from both sides effectively isolates x:

 340 = 274 + x

- 274    -274

------------------------

  66      =    x

The fifth student's mark was 66.

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A line intersects the point (3,-4) and has a slope of 17. What is the slope-intercept equation for this line? y = 17x + [?]​
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4 0
3 years ago
Please help to solve this please with steps.
Blababa [14]

Answer:

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

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now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

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3 years ago
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