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Ahat [919]
3 years ago
5

Write words to match the expression, 3 + (4 × 12)

Mathematics
2 answers:
konstantin123 [22]3 years ago
6 0
Three added to the product of four and twelve

or

The product of four and twelve added by three
Whitepunk [10]3 years ago
5 0
"The product of 4 and 12, then add 3"
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What is x? I tried it but I don’t think I did it right.
sattari [20]

Answer:

x = 4

Step-by-step explanation:

When a tangent and a secant are drawn from an external point to a circle.

Then the product of the external part of the secant and the entire secant and the square of the measure of the tangent are equal, hence

x(x + 5) = 6²

x² + 5x = 36 ( subtract 36 from both sides )

x² + 5x - 36 = 0 ← in standard form

(x + 9)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 4 = 0 ⇒ x = 4

However, x > 0 ⇒ x = 4

8 0
3 years ago
102% of 250 please tell me
Lerok [7]
102% of 250 = 255            Hope this helps  ( :
4 0
3 years ago
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Math is annoying! Can someone help me please?
lord [1]
16.  would be C since they both consist of the same variable to the same power

17. x-2x+7-9+4x
     c. 3x-2
18. -4(3a-5). You would multiply -4 by 3 a, and -4 by -5. It turns to
      -4(3a)-4(-5)
     a. -12a+20
4 0
3 years ago
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
Use FOIL to explain how to find the product of (a + b)(a − b). Then describe a shortcut that you could use to get this product w
xenn [34]

Answer:

The product of (a+b)(a-b)  is a^2 - b^2

Step-by-step explanation:

Use FOIL to explain how to find the product of (a + b)(a − b)

FOIL is

Multiply First terms : a*a = a^2

Multiply Outside terms : a* -b = -ab

Multiply Inner  terms : b * a= ab

Multiply last terms : b * -b = -b^2

now we combine all the terms

a^2 -ab+ab - b^2

combine like terms

a^2 - b^2

The product of (a+b)(a-b)  is a^2 - b^2

Shortcut is we apply an identity

a^2 - b^2 = (a+b)(a-b)

8 0
3 years ago
Read 2 more answers
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