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slega [8]
4 years ago
10

Car A and Car B start together. Car A travels once around a circular track at 30 MPH. Car B travels in the opposite direction at

20 MPH until he passes Car A. From this point, at what speed must Car B travel to finish once around the track at the same time that Car A does?
Mathematics
1 answer:
storchak [24]4 years ago
7 0

After they start, the speed at which the cars are moving toward each other is (30 mph) + (20 mph) = 50 mph. At the time they meet, Car A will have traveled 30/50 = 0.6 of the distance around the track, while Car B will have traveled the other 0.4 times the distance.

Car A will have to cover only 0.4 times the length of the track before being at the start. This is 0.4/0.6 = 2/3 of the distance Car A has already traveled, so is expected to take 2/3 of the time already taken.

Car B must cover 0.6/0.4 = 3/2 times as much track as it has already covered. In order to do so, its speed will need to be

... speed ratio = (distance ratio)/(time ratio) = (3/2)/(2/3) = 9/4

times what it has been so far.

Car B's speed will need to be

... 9/4 × 20 mph = 45 mph

to finish at the same times car A does.

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Jane is using a carpenter’s square at eye level to determine the height of the tree, as shown in the figure. She is standing 9 f
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Applying the trigonometry ratio, TOA, the measurement that is closest to the height of the tree in feet is: D. 21

Recall:

Trigonometry ratios can be applied to solve any right triangle for missing side lengths or angles. They are denoted with the acronym, SOH CAH TOA.

Using trigonometry ratio, TOA, find the length of the side of the tree in the bigger triangle as follows:

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