Question

The sum of two integers is 6 and the difference between the numbers is 40. Find the numbers

Answer 1

Set up a system of equations.

X+y=6
Y-x =40

Substitution method.

Y=6-x

(6-x)-x =40
6-2x=40
-2x=34
X= -17

Plug it back into the equation.
-17+y=6
Y=33

(-17,33) is one of the possible answers.

Answer 2

The equation to be solved:

x + x + 40 = 6

x = the missing number.

x + 40 = the missing number + 40 since the difference between the two is of 40.

6 = the sum of the both missing numbers.

Equation solved step-by-step:

x + x + 40 = 6

2x + 40 = 6

2x = 6 - 40

2x = -34

x = -34 / 2

x = -17

If x = -17 than the other number is equal to x + 40

x + 40 =

-17 + 40 =

23

-17 and 23 are the two missing numbers. To proove it, we will have to do the sum an see if it equals 6:

-17 + 23 = 6

Answer:

$\boxed{\bf~The~two~numbers~are~-17~and~23.}$

Hope it helped,

Happy homework/ study/ exam!