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4vir4ik [10]
3 years ago
15

A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo

ng. How y'all is the tower?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

\Rightarrow \frac{h}{s} =k    [Height of object is denoted by h and shadow is denoted by s]

Then,

\frac{h_1}{s_1} =k       [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

\frac{h_2}{s_2}=k      [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

\frac{h_1}{s_1}=\frac{h_2}{s_2} =k

\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}............(1)

Given h_1 = 2.6 m  ,s_1=1.03m  and   s_2=46.25m

Putting the value of h_1,s_1 and s_2  equation (1)

\frac{2.6}{1.03}=\frac{h_2}{46.25}

\Rightarrow h_2 \times1.03= 2.6\times 46.25          [cross multiplication]

\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}

\Rightarrow h_2= 116.75

Therefore the height of the tower is 116.75 m.

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