Answer:
.9 or 90%
.1 or 10%
Step-by-step explanation:
E= Exam
P=Paper
E= .71
P= .45
E∩P=.26
A.) E∪P=?
E∪P= E+P-E∩P
.71+.45-.26= .9
B.) E'∩P' = (E∪P)'
(E∪P)' = 1-.9 = .1
D'
you can't use the same single letter to mark a new point.
Convert <span>6\frac{3}{8}<span>6<span><span>8</span><span>3</span><span></span></span></span></span><span> to improper fraction. Use this rule: </span><span>a \frac{b}{c}=\frac{ac+b}{c}<span>a<span><span>c</span><span>b</span><span></span></span>=<span><span>c</span><span><span>ac+b</span></span>:</span></span></span>
∣8<span><span><span><span>6×8+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1<span>∣
</span></span>Simplify <span>6\times 8<span>6×8</span></span><span> to </span>48: <span><span><span><span><span>
</span>8</span><span><span>48+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span>Simplify <span>48+3<span>48+3</span></span><span> to </span>51:</span><span><span><span><span><span>
</span>8</span><span><span>51</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span> Make the denominators the same:
<span><span><span>51</span><span>/8</span></span>−2×<span><span>8</span><span>8</span><span>
</span></span></span><span>Simplify. Denominators are now the same:
</span>
<span><span><span>51</span><span>/8</span></span>−<span><span>8</span><span><span>16</span></span><span>
</span>
</span></span>Join the denominators: \frac{51-16}{8}<span><span>8</span><span><span>51−16</span></span><span>
</span>
etc.. and your answer will be 14
</span></span>
Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with 
rows and 
columns is 
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is ![\left[\begin{array}{ccc}0&-4&6\\2&-10&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-4%266%5C%5C2%26-10%264%5Cend%7Barray%7D%5Cright%5D)
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is 
as it has 3 rows and 2 columns.
The order of matrix 3B is 
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
