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Crank
3 years ago
9

Sin(cosx) = 1 solve for x

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

There is no solution for x.

Step-by-step explanation:

We are given that \sin (\cos x) = 1 and we have to solve for x.

Let us assume that \cos x = \theta then \sin \theta = 1 ........ (1)

Now, we know that for any value of x the value of cos x lies between 1 to - 1.

Hence, 1 \geq  \cos x \geq  - 1  for all x.

⇒ 1 \geq  \theta \geq  - 1

Now, for 1 \geq  \theta \geq  - 1, the value of \sin \theta can never be equal to 1.

Hence, there is no solution for x. (Answer)

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Write the ratio as a percent.
natali 33 [55]

Answer:

62%

Step-by-step explanation:

This one's easy to solve as a percentage because the total number was 100 to begin with. Simply divide the number of employed students by the total amount of students, 62/100, which gets 0.62, or 62%.

5 0
3 years ago
Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8
Lelu [443]
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5 0
3 years ago
Mark is organizing a trip to the movies for his family. He has $30 to spend. Adult tickets cost $5 each and children's tickets c
Alisiya [41]

Answer:

5y+3y=30

Step-by-step explanation:

7 0
3 years ago
who swam the fastest. tawni 50m 40.8 seconds pepita 100m butterfly 60.2 seconds or Susana 200 medley 112.4 seconds
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8 0
3 years ago
I need help. I don't know how to solve the problem at all.
dybincka [34]
This problem is a real bear.  Whoever wrote it has a sense of humor, and expects
a lot from you ... probability, permutations, combinations, and geometry.

<u>First, let's talk about probability:</u>
The probability of something happening is (the number of outcomes that meet your description) divided by (the total number of all possible outcomes).

<u>#62:</u>
There are 4 points on the drawing.  How many different ways could you pick
two of them ?

The first one you pick could be any one of 4 points. 
For each of those, the other point could be any one of the remaining 3. 
So the total number of ways to pick 2 points out of 4 is (4 x 3) = 12 ways.
But wait !  Whether you pick 'A' and then 'C', or pick 'C' and then 'A', you still wind up with the same two points. So, although there are 12 ways to pick them, there are only 6 different distinct pairs of points.

OK.  How many of those pairs are collinear ?  ANY two points lie on the same line, because a line can always be drawn between any two points.  So out of the 6 different possible pairs of points, ALL 6 pairs are collinear.  The probability of picking a pair that are collinear is 100% .

<u>#63:</u>
There are 4 points on the drawing.  How many different ways could you pick
three of them ?
The first one you pick could be any one of 4 points.  For each of those ...
The second point could be any one of the remaining 3.  For each of those ...
The third point could be either one of the remaining 2.
So the total number of ways to pick 3 points out of 4 is (4 x 3 x 2) = 24 ways.
But wait !  Whether you pick ABC, ACB, BAC, BCA, CAB, or CBA, you still wind up with the same three points. So, although there are 24 ways to pick them, there are only 4 different distinct sets of three points.

OK.  How many sets of 3 points in this drawing are collinear ?
There is only one !  ONLY A, B, and C are collinear.

Probability = 1 out of 4 = 1/4 = 25 percent .

<u>#64:</u>
In the last problem, we saw that there are 4 distinct sets of three points.
How many of them are coplanar ?
They ALL are.  A plane can be drawn through ANY three points.
So whichever three points you pick, they are coplanar.
The probability is  4 out of 4 = 100 percent.

Thank you for your 5 points.  I shall cherish them.

7 0
3 years ago
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