If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Step-by-step explanation:
:? O ghhbbvbbbnhhggvhgffghhhhfgghtf
565.487 units cubed
hope this helps:)
Answer: x=15
Step-by-step explanation: Let's solve your equation step-by-step.
x+
1
/2
(x−5)=20
Step 1: Simplify both sides of the equation.
x+
1
/2
(x−5)=20
x+(
1
/2
)(x)+(
1
/2
)(−5)=20(Distribute)
x+
1
/2
x+ −5
/2
=20
(x+
1
/2
x)+(
−5
/2
)=20(Combine Like Terms)
3
/2
x + −5
/2
=20
3
/2
x + −5
/2
=20
Step 2: Add 5/2 to both sides.
3
/2
x + −5
/2 + 5
/2
=20+
5
/2
3
/2
x= 45
/2
Step 3: Multiply both sides by 2/3.
(
2
/3
)*(
3
/2
x)=(
2
/3
)*(
45
/2
)
x=15
Answer:
9........I will post process in comments because you are needing this right now
