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3 years ago

Lesson 2 semester B exam algebra 1B unit 7

Mathematics

2 answers:

slava [35]3 years ago

8 0

Answer:

do you have all the answers for the exam, you can get 100 points

brainly.com/question/14257403

Elodia [21]3 years ago

4 0

<h2>Answer:</h2>

720 pounds

<h2>Step-by-step explanation:</h2>

Initially, we have that the amount of algae in the pond is $90pounds$ . Every four hours the amount of algae doubles. If we called $t$ the time and $W$ the amount of algae, we have that:

$At \ t=0 \ hours, \ w=90 \ pounds \\ \\ At \ t=4 \ hours, \ w=2(90)=180 \ pounds \\ \\ At \ t=8 \ hours, \ w=2(180)=360\ pounds \\ \\ At \ t=12 \ hours, \ w=2(360)=720 \ pounds$

Finally, <em>after 12 hours the amount of algae in the pond is 720 pounds</em>

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Let S = {1, 4, 6, 9}

tankabanditka [31]

Answer:

There are 8 sets B that satisfy the conditions.

Step-by-step explanation:

We have to find the total subsets of S that have 1 as an element.

Subsets B with one element: {1}

Subsets with two elements: {1,4}, {1,6}, {1, 9}

Subsets with three elements: {1,4,6}, {1,4,9}{1,6,9}

Subsets with four elements: {1,4,6,9}

Therefore, B = {1, {1,4}, {1,6}, {1, 9}, {1,4,6}, {1,4,9}, {1,6,9}, {1,4,6,9}}

6 0

3 years ago

Please help me with this please

jekas [21]

24/100 like NewTube
30/100 like Friendspace
14/100 like NaviChat
12/100 like other
20/100 like none

100 - 20 = 80
Therefore, exactly 80% of the grandparents have a favourite social media website. The first statement is most likely to be correct

5 0

3 years ago

The interior angles of a hexegon are in the ratio 3:3:4:5:6:7. Find; (a) The size of the smallest angle. (b) The size of the lar

elena-s [515]

Answer:

a) 77.13

b) 179.97

Step-by-step explanation:

3x + 3x + 4x + 5x + 6x + 7x = (6 - 2) × 180

28x = 720

x = 720/28

x ≅ 25.71

3 × 25.71 = 77.13 = smallest angle

7 × 25.71 = 179.97 = largest angle

3 0

3 years ago

Simplify.<br> -5x^4(-3x^2+4x-2)

Amiraneli [1.4K]

Answer:

3x^6 - 4x^5 + 2x^4

Step-by-step explanation:

Given

-5x^4 ( -3x^2 + 4x - 2)

Step 1 : open the bracket with -5x^4

-5x^4 * -3x^2= 15x^6

Hint: - * - = +

x^4 * x ^2 = x^ 4+2 = x^6

-5x^4 * + 4x = - 20x^5

Hint: - * + = -

x^4 * x = x^4 + 1 = x^5

(x is always raise to the power of 1 but we don't write it or less it is greater than 1 e.g. 2 , 3 ,4, ..........)

-5x^4 * -2 = 10x^4

Hint: - *- = +

Let's combine the answers

15x^6 - 20x^5 + 10x^4

We can look for a factor that can go through as in that can divide all without a reminder

Factors of

15 - 3 * 5

1 * 15

20 - 4 *5

2 *10

1 * 20

10 - 2*5

1 * 10

Since the factor of 5 is common in all, so we are using 5 to divide through

15x^6 - 20x^5 + 10x^4

Using 5 to divide through

15x^6 / 5 - 20x^5 / 5 + 10x^4 / 5

= 3x^6 - 4x^5 + 2x^4

4 0

4 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.

Artist 52 [7]

Answer: 0.0250

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.0 minutes.

We know that the uniform distribution is also known as rectangular distribution.

Density function for uniform distribution : $f(x)=\dfrac{1}{b-a}$

$=\dfrac{1}{60-50}=\dfrac{1}{10}$

Now, the probability that a given class period runs between 51.25 and 51.5 minutes :-

$\int^{51.5}_{51.25}f(x)\ d(x)\\\\ \int^{51.5}_{51.25}\dfrac{1}{10}\ dx\\\\=\dfrac{1}{10} [x]^{51.5}_{51.25}\\\\=\dfrac{1}{10}(51.5-51.25)=0.0250$

Hence, the probability that a given class period runs between 51.25 and 51.5 minutes = 0.0250

3 0

3 years ago