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WARRIOR [948]
2 years ago
7

A shipping company claims that 90% of its packages are delivered on time. Jenny noticed that out of the last 10 packages shipped

, 2 were late. What is the probability that 2 out of 10 randomly selected shipments would be late? 0. 04 0. 10 0. 19 0. 43.
Mathematics
1 answer:
nasty-shy [4]2 years ago
3 0

The probability that 2 out of 10 randomly selected shipments would be late is 0.19.

<h2>Given </h2>

A shipping company claims that 90% of its packages are delivered on time.

Jenny noticed that out of the last 10 packages shipped, 2 were late.

<h2>What is probability?</h2>

The probability of success and failure remain the same throughout the trials.

The probability that 2 out of 10 randomly selected shipments would be late is given by;

\rm =^{10}C_2 \times (\dfrac{2}{10})^2 \times (0.8)^8\\\\=45 \times 0.04\times 0.16\\\\ = 0.19

Hence, the probability that 2 out of 10 randomly selected shipments would be late is 0.19.

To know more about Probability click the link given below.

brainly.com/question/5053059

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3 years ago
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Answer:

Please check the explanation.

Step-by-step explanation:

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f(x) = 3x + x³

Taking differentiate

\frac{d}{dx}\left(3x+x^3\right)

\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'

=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

solving

\frac{d}{dx}\left(3x\right)

\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'

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\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1

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now solving

\frac{d}{dx}\left(x^3\right)

\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}

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Thus, the expression becomes

\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

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