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WARRIOR [948]
2 years ago
7

A shipping company claims that 90% of its packages are delivered on time. Jenny noticed that out of the last 10 packages shipped

, 2 were late. What is the probability that 2 out of 10 randomly selected shipments would be late? 0. 04 0. 10 0. 19 0. 43.
Mathematics
1 answer:
nasty-shy [4]2 years ago
3 0

The probability that 2 out of 10 randomly selected shipments would be late is 0.19.

<h2>Given </h2>

A shipping company claims that 90% of its packages are delivered on time.

Jenny noticed that out of the last 10 packages shipped, 2 were late.

<h2>What is probability?</h2>

The probability of success and failure remain the same throughout the trials.

The probability that 2 out of 10 randomly selected shipments would be late is given by;

\rm =^{10}C_2 \times (\dfrac{2}{10})^2 \times (0.8)^8\\\\=45 \times 0.04\times 0.16\\\\ = 0.19

Hence, the probability that 2 out of 10 randomly selected shipments would be late is 0.19.

To know more about Probability click the link given below.

brainly.com/question/5053059

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denis-greek [22]

Responda:

GRÁFICO DE TEMPO DE VELOCIDADE

Explicação passo a passo:

Para a pergunta, encontre o gráfico de velocidade-tempo no anexo.

O gráfico que melhor representa a velocidade desse avião em função do tempo é o gráfico velocidade-tempo. O gráfico de velocidade e tempo é um gráfico que representa o movimento de um objeto esquematicamente usando linhas. Ele é plotado em um plano de coordenadas com o eixo xe o eixo y.

A função de velocidade é posicionada no eixo y, enquanto o tempo gasto ao longo da viagem está no eixo x.

Pelo anexo, pode-se ver que o avião acelera em OA, possui velocidade constante em AB e CD e tem aceleração (desaceleração) negativa em BC e DE.

4 0
4 years ago
A study was done to determine the average number of homes that a homeowner owns in his or her lifetime. For the 50 homeowners su
ipn [44]

Answer:

The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0096

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0096\frac{3.8}{\sqrt{50}} = 1.1

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 5.1 - 1.1 = 4

The upper end of the interval is the sample mean added to M. So it is 5.1 + 1.1 = 6.2.

The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).

7 0
3 years ago
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KonstantinChe [14]

a)0.43^5*0.57^5

b)0.43^6*0.57^4

c)0.43^3*0.57^7+0.43^2*0.57^8+0.43^1*0.57^9+0.57^10

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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