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ki77a [65]
3 years ago
11

Can you help me with 22-25

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
22 - y(5+1,5x). Y=number of pizzas X=number of toppings.
You might be interested in
HELP ME WITH THE EXERCISES PLEAASE
Zinaida [17]
1.

1=87 corresponding angle.
2=180-87=93


2.

1=78 corresponding angles
2=78 verticle angles


3.

Set it up as (6x - 11) = 37
37 + 11 =48

6x = 48

x = 8


4.

Take 142 and see that it is supplementary to angle 2 so 180-142 = 38

38 is corresponding to the equation 2(x + 9)

So 2(x + 9) =38
Distributive property

2x + 18 = 38
38-18=20

2x =20

x = 10

Angle 2 is equal to 38 from supplementary to 142


I’m pretty positive about 1-3 but 4 maybe not be correct. But most likely these are correct
6 0
3 years ago
A swimming pool is filled with water by using two taps A and B. Alone, it takes tap A 3 hours less than B to fill the same pool.
iris [78.8K]

Answer:

Tap A 3hrs

Tap B 6hrs

Step-by-step explanation:

Let the volume of the swimming pool be Xm^3.

Now, to get the appropriate volume, we know we need to multiply the rate by the time. Let the rate of the taps be R1 and R2 respectively, while the time taken to fill the swimming pool be Ta and Tb respectively.

x/Ta= Ra

x/Tb= Rb

X/(Ra + Rb)= 2

Ta = Tb - 3

From equation 2:

X = 2( Ra + Rb)

Substituting the values of Ra and Rb Using the first set of equations

X = 2( x/Ta + x/Tb)

But Ta = Tb - 3

1/2 = 1/(Tb - 3)+ 1/Tb

0.5 = (Tb + Tb-3)/Tb(Tb - 3)

At this juncture let’s say Tb = y

0.5 = (2y - 3)/y(y - 3)

y(y-3 ) = 4y - 6

y^2 -3y - 4y + 6 = 0

y^2 -7y + 6= 0

Solving the quadratic equation, we get y =

y = Tb = 6hrs or 1hr

We remove one hour as we know that Tap A takes 3hrs left than tap B and there is nothing like negative hours

Now, we get Ta by Tb -3 = 6 - 3 = 3hrs

5 0
3 years ago
Matrix bought a 5-pack of white t-shirts for 26 dollars what is the price per t-shirt
defon

Answer:

$5.20 per shirt

Step-by-step explanation:

26 ÷ 5 = 5.20

6 0
3 years ago
Read 2 more answers
Watch help video
finlep [7]

3√5

The distance between two points on an XY plane is calculated using the distance formula, which is employed in coordinate geometry or Euclidean geometry. The x-coordinate, often known as the abscissa, is a point's separation from the y-axis. The y-coordinate, often known as the ordinate, refers to a point's separation from the x-axis. A point on the x-axis has coordinates of the form (x, 0), and a point on the y-axis has coordinates of the form (0, y). We utilize the Pythagoras theorem in this case to determine the separation between any two points in a plane.

Distance formula = √ ( x₁ - x₂)² + ( y₁ - y₂)²

                                = √ 6² + 3²

                                =3√5

To learn more about distance formula, refer to brainly.com/question/7243416

#SPJ9

7 0
1 year ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
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