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2 years ago

T/-7>10 solve this inequallity

Mathematics

1 answer:

Zepler [3.9K]2 years ago

8 0

Multiply both sides by -7 and switch the sign. t<-70

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Solve it ......<br> <img src="https://tex.z-dn.net/?f=3x%2B4%3D28" id="TexFormula1" title="3x+4=28" alt="3x+4=28" align="absmidd

o-na [289]

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$\blue\textsf{\textbf{Question:-}}}}$

Solve 3x+4=28

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First, subtract 4 on both sides:-

$\tt{3x=28-4}$

$\tt{3x=24}$

Divide by 3 on both sides:-

$\dashrightarrow\bigstar\boxed{\boxed{\bold{x=8}}}\dashleftarrow$

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Irina18 [472]

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what are the angle measures of the triangle? a)30, 60, and 90 b)45, 45, and 90 c)60,60,and 60 d)they cannot be determined.

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2 years ago

Verifying Trig Functions

anzhelika [568]

Answer:

The answer to your question is below

Step-by-step explanation:

csc α - cot α = $\frac{sin \alpha }{1 + cos \alpha }$

Work with the left part

$\frac{1}{sin\alpha } - \frac{cos \alpha }{sin \alpha}$

Simplify

$\frac{1 - cos\alpha }{sin\alpha }$

Multiply by the reciprocal

$\frac{1 - cos\alpha }{sin \alpha } x \frac{1 + cos\alpha }{1 + cos\alpha }$

Simplify

$\frac{1 - cos^{2}\alpha}{sin\alpha (1 + cos\alpha)}$

Remember that

sin²α = 1 -cos²α

Substitute the previous equation

$\frac{sin^{2}\alpha }{sin\alpha(1 + cos\alpha ) }$

Simplify

$\frac{sin\alpha}{1 + cos \alpha}$

The identity i proved.

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2 years ago