Quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Step-by-step explanation:
Write a quadratic function h whose zeros are 5 and -7
If 5 and -7 are zeros of quadratic function then:
x=5 and x=-7
or x-5 = 0 and x+7=0
So, Finding quadratic equation:
So, quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Keywords: Quadratic Function
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You and your friend made 13 each
Answer:
x = 1
y = 3
Step-by-step explanation:
<h2>
<em><u>Substitution Method</u></em><em><u>:</u></em></h2>
Step 1:
Name The Equation
4x + y = 7 ...(1)
3x + 2y = 9 ...(2)
Step 2:
From Equation (1) we get,
4x = 7 - y
i.e.,
x = 7 - y/4
Step 3:
Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)
i.e.,
3(7 - y/4) + 2y = 9
21 - 3y/4 + 2y = 9
21 - 3y + 8y/4 = 9
21 - 3y + 8y = 9 * 4
21 + 5y = 36
5y = 36 - 21
5y = 15
y = 15/5
<em><u>y = 3</u></em>
Step 4:
Substitute the value of <em><u>y = 3</u></em> in equation (1)
4x + y = 7
i.e.,
4x + (3) = 7
4x + 3 = 7
4x = 7 - 4
4x = 4
x = 4/4
<em><u>x = 1</u></em>
<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>
4x + y = 7 i.e., <em>4(1) + (3) = 7</em>
3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>
Answer:
<em><u>f</u></em><em><u>(</u></em><em><u>x</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>6</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>2</u></em><em><u>0</u></em>
Step-by-step explanation:
Answer:
50.5 degrees
Step-by-step explanation:
Since this is a parallelogram then...
Angle U + Angle R = 180
3x+4+9x-10=180
Combine like terms
12x-6=180
Add 6 to both sides
12x=186
Divide both sides by 12
x=15.5
Now we plug 15.5 in for x to find Angle U
3(15.5)4=46.5+4=50.5
Angle U = 50.5 degrees
