Is 5 degrees above zero a negative quantity always never or sometimes

Mathematics

1 answer:

7nadin3 [17]2 years ago

5 0

Answer:

never

Step-by-step explanation:

5 degrees above zero is never a negative, it's positive

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One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers

Reptile [31]

Let,
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)

$\frac{1}{x} + \frac{1}{y}= \frac{45}{4}$ ...................................equation (2)

Taking equation (2)
$\frac{1}{x} + \frac{1}{y}= \frac{45}{4}$

Substituting the value of "x" from equation (1), we get,

$\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}$

$\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}$

$\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}$

$\frac{1+4}{4y} = \frac{45}{4}$

$\frac{5}{4y} = \frac{45}{4}$

Cross multiplying, we get,

$5*4 = 45*4y$

$20 = 180y$
<u />
$\frac{20}{180} = y$

$\frac{1}{9} = y$

$y = \frac{1}{9}$

Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

$x = 4( \frac{1}{9} )$

$x= \frac{4}{9}$

So, the numbers are $\frac{1}{9}$ and $\frac{4}{9}$

7 0

2 years ago

Read 2 more answers

Whats the answer for w^5+4w^4+10w^3+40w^2

Mazyrski [523]

Answer:

w^2*(w+4)*(w^2+10)

Step-by-step explanation:

w^5+4w^4+10w^3+40w^2

w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))

w^2*(w+4)*(w^2+10)

6 0