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svlad2 [7]
2 years ago
7

Using the quadratic formula to solve x2 = 5 - X, what are the values of X?

Mathematics
1 answer:
sdas [7]2 years ago
3 0

Answer:

The answer is

<h3>x =  \frac{ - 1 +  \sqrt{21} }{2}  \:  \:  \: or \:  \:  \: x =  \frac{ - 1 -  \sqrt{21} }{2}</h3>

Step-by-step explanation:

x² + x - 5 = 0

Using the quadratic formula

That's

<h3>x =  \frac{  - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}</h3>

From the question

a = 1 , b = 1 , c = - 5

Substitute the values into the above formula and solve

We have

<h3>x =  \frac{ - 1\pm \sqrt{ {1}^{2} - 4(1)( - 5) } }{2(1)}  \\ x =  \frac{ - 1\pm \sqrt{1  + 20 } }{2}  \\ x =   \frac{ - 1\pm \sqrt{21} }{2}</h3>

We have the final answer as

<h3>x =  \frac{ - 1 +  \sqrt{21} }{2}  \:  \:  \: or \:  \:  \: x =  \frac{ - 1 -  \sqrt{21} }{2}</h3>

Hope this helps you

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