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ivolga24 [154]
3 years ago
10

Whats the gcf of n^3t^2 and nt^4

Mathematics
1 answer:
melomori [17]3 years ago
4 0
GCF-Greatest\ Common\ Factor\\\\n^3t^2=nt^2\cdot n^2\\nt^4=nt^2\cdot t^2\\\\GCF(n^3t^2;\ nt^4)=\boxed{nt^2}
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Six years after a tree was planted, its height was 7 feet. Nine years after it was planted, its height was 16 feet. Which of the
pychu [463]
Considering that the grows at a constant rate we can form an equation where x = how many years after it was planted
and y = its height

Now we just need to find how many feet it grows each year. To do that we just need to compare its height from a certain age to another:
6 years after it was planted : 7 feet,
so x=6 and y = 7

9 years after it was planted: 16 feet
so x= 9 y=16

With thay we can conclude that in 3 years , the tree grew 9 feet. To discover how much the tree grow each year we just nee to divide 9 feet by 3 years which is 3 feet every year.

To write the equatopn now we just need to find the y-intercept which we can discover by setting x to 0:
If in 6 years after the tree was planted it is 7 feet long , we can discover how long it was when it was planted by subtracting 6 years of growth (The slope ) which is 3
7 - 6(years)×3(feet the tree grow each year)
7 - 18 = -11
The tree was -11 feet long when it was planted
which is our y-intercept
( I know it doesnt make sense , but if you apply to a graph it will make more sense )


Now we can make the equation
y = 3x -11
7 0
3 years ago
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

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8 0
3 years ago
Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

2.50

Step-by-step explanation:

the pattern shown in the miles driven goes up each time by 5000, stating it's going up by a constant of 5000. the cost goes up each time by 2000.

divide 5000/2000 which would give you 2.5

round it by two decimal places which gives you 2.50

7 0
3 years ago
I will give brainliest if correct !!
qwelly [4]

Answer:

acute isosceles

Step-by-step explanation:

3 0
3 years ago
George studied 3/4 of an hour on Monday and 7/8 of an hour on Tuesday. How long did he study altogether on both days?
7nadin3 [17]

so you would add 3/4 and  7/8.  so thats 1 1/2

3 0
3 years ago
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