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Alenkasestr [34]
2 years ago
9

Find the measure of the arc or central angle indicated. Assume that lines which appear to be diameters are actual diameters. 7)

MZDGC 8) mZSXW F --212 12.7 12x - SIG W 370 B 4x-SE 15 + 4x C D 21x + 8 Find the measure of the arc or angle indicated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are tangent. 11) Find mZSTV 12) Find mJMK T 6x U 127x + 1 6 + 10x M S L 63.r + 1 160° 13) Find mQS 14) 500 U P D G, F 155 “ e 19x - 2 E 15x U R S 190°​

Mathematics
1 answer:
oee [108]2 years ago
5 0

Answer:

Stcated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are tangent. 11) Find mZSTV 12) Find mJMK T 6x U 127x + 1 6 + 10x M S L 63.r + 1 160° 13) Find mQS 14) 500 U P D G, Fep-by-step explanation:

dicated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are ta

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3 years ago
12 times 1/8 how do you cross multiply this
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3 years ago
Read 2 more answers
A die with six faces has the number 1 painted on three of its faces, the number 2 painted on 2 of its faces, and number 3 on one
salantis [7]

Answer:

a) S = {1, 2, 3}

b) P(odd number) = \frac{2}{3}

c) No

d) Yes

Step-by-step explanation:

a) The sample space is the set of all possible outcomes. By definition, the elements of a set should not be repeated. Hence, the sample space S = {1, 2, 3}

However, the sample is not equiprobable because each element has different probabilities.

b) P(odd number) = \frac{number of odd digits}{number of faces}=\frac{4}{6}=\frac{2}{3}

Note that the odd numbers are 1 (on three faces) and 3 (on one face).

c) The fact the die has been biased does not change the possible outcomes. It only changes the probability of getting any given number.

d) Because the 3-face has been loaded, this probability changes. In fact, it is calculated thus:

Let's assume the probability for 1 or 2 is x. Then that of 3 is 2x(because it is twice the others). The sum of probabilities must be 1.

x+x+x+x+x+2x=1

7x=1

x=\frac{1}{7}

P(odd number) = 3\timesProb(1) + Prob(3)

= 3\times\frac{1}{7}+\frac{2}{7} = \frac{5}{7}

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