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Alenkasestr [34]
2 years ago
9

Find the measure of the arc or central angle indicated. Assume that lines which appear to be diameters are actual diameters. 7)

MZDGC 8) mZSXW F --212 12.7 12x - SIG W 370 B 4x-SE 15 + 4x C D 21x + 8 Find the measure of the arc or angle indicated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are tangent. 11) Find mZSTV 12) Find mJMK T 6x U 127x + 1 6 + 10x M S L 63.r + 1 160° 13) Find mQS 14) 500 U P D G, F 155 “ e 19x - 2 E 15x U R S 190°​

Mathematics
1 answer:
oee [108]2 years ago
5 0

Answer:

Stcated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are tangent. 11) Find mZSTV 12) Find mJMK T 6x U 127x + 1 6 + 10x M S L 63.r + 1 160° 13) Find mQS 14) 500 U P D G, Fep-by-step explanation:

dicated. 9) Find mRL 10) Find mZSRT K T 16x-1 15x + 3 30x + 4 32x - 4 S L Find the measure of the arc or angle indicated. Assume that lines which appear tangent are ta

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Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.
alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

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Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

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