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FinnZ [79.3K]
3 years ago
5

Is-2 an integer or rational #

Mathematics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

hello your answer is rational  −2 is a rational number because we can express it as a ratio of two whole numbers.

Step-by-step explanation:

hope i helped

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How can you find the side of a triangle only using angles 33 degrease, 49 degrees, and 98 degrees, and one side which is 100m. I
kumpel [21]

Answer:

72.17 m to the nearest hundredth.

Step-by-step explanation:

It is sin not cos.

We use the Sine Rule to do this

a / sin A = b / sin C = c / sin C.

Here we have:

100 / sin 49 =  x / sin 33

x =  100 * sin 33 / sin 49

= 72.17 m.

3 0
3 years ago
Read 2 more answers
Write 5^3 x √5 as a single power of 5
MakcuM [25]
√5 = 5^(1/2)

Multiplying two number with the same base has as result a number with the same base and the sum of the exponents so:

1/2 + 3 = 7/2
which means
5^3 x 5^(1/2) = 5^(7/2)
5 0
2 years ago
What’s the ordered pairs of <br> y = 10x + 18? The image is down below.
kompoz [17]
Okay 2
Really
4
During
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67
3 0
3 years ago
Read 2 more answers
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
Five plus two times 50 divided by ten divided by 49 divided by seven
Flauer [41]

Answer:

0.0437

Step-by-step explanation:

5+2×50÷10=15 15÷7=0.0437

3 0
3 years ago
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