Answer:
Part 1) Helen's age is 32 years old and Jane's age is 24 years old
Part 2) 13 twenty-dollar bills
Step-by-step explanation:
Part 1) Helen is 8 years older than Jane. Twenty years ago Helen was three times as old as Jane. How old is each now and what is the equation?
Let
x----> Helen's age
y---> Jane's age
we know that
x=y+8 ----> equation A
(x-20)=3(y-20) -----> equation B
substitute equation A in equation B and solve for y
(y+8-20)=3(y-20)
y-12=3y-60
3y-y=60-12
2y=48
y=24 years
Find the value of x
x=y+8
x=24+8=32 years
Part 2)
Let
x-----> the number of five-dollar bills
y----> the number of twenty-dollar bills
we know that
5x+20y=305 -----> equation A
y=x+4 ------> x=y-4 ------> equation B
substitute equation B in equation A and solve for y
5(y-4)+20y=305
5y-20+20y=305
25y=325
y=13 twenty-dollar bills
Find the value of x
x=y-4
x=13-4=9 five-dollar bills
Answer:
(4.5,-7)
Step-by-step explanation:
you add the x coordinates then divide them by 2
And then add the y coordinates then divide them by 2 also
Because <span>−8</span><span> does not contain the </span>variable<span> to solve for move it to the other side of the </span>equation<span> by adding </span>8<span> to both sides.
</span><span>5x=8+37
</span>Add 8<span> and </span>37<span> to get </span><span>45.
</span><span>5x=45
</span>Divide<span> each </span>term<span> by 5.
</span>x=<span>9
</span>
x is equal to 9
Answer:
q = -2
Step-by-step explanation:
when solving 12q >= -24 you get
q >= -2 (12 divides 24 by 2)
therefore q is greater or equal to -2.
Answer is 3a²b (a + b)
Step-by-step explanation:
- Step 1: Find 3a² (ab²+b²)
⇒ 3a² (ab²+b²) = 3a³b + 3a²b² = 3a²b (a + b)
