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tiny-mole [99]
3 years ago
12

When a customer places an order at Ying Ying's bakery, there is an 8\%8%8, percent probability that the customer will report a f

ood allergy. One day, 121212 customers place orders at Ying Ying's bakery.
Assuming that each of the 121212 customers is equally likely to report a food allergy, what is the probability that at least one customer will report a food allergy?
Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer: 0.6323

Step-by-step explanation:

Given : The proportion of customer will report a food allergy : p=0.08

One day, 121 customers place orders at Ying Ying's bakery.

If we assume that each of the 12 customers is equally likely to report a food allergy , then we can use Binomial distribution.

Formula for Binomial probability distribution:

P(X=x)=^nC_xp^x(1-p)^{n-x}

, where P(x)= probability of getting success in x trials, n= sample size , p= probability of getting success in each event.

As per given , we have n= 12

p=0.08

Let x denotes the customer will report a food allergy.

Then, the probability that at least one customer will report a food allergy will be :

P(x\geq1)=1-P(x

Hence, the required probability = 0.6323

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S_A_V [24]
Given:
t A = 2.4 h
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plug in the numbers
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3 years ago
the data set represents the total number of tickets each person purchased for a play. 0,0,1,1,1,2,2,2,4 4, what is the median of
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2(x-3)=14<br> -5(x-1)= 40<br> 12(X+20)=24
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A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

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Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
3 years ago
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