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Julli [10]
2 years ago
8

Question is the attachment

Mathematics
1 answer:
sweet [91]2 years ago
5 0

Answer:

180

^

120 Green, 60 Red

^                     ^

Bruised Green = 30, Not Bruised Green = 90/Bruised Red = 12, Not Bruised Red = 48

Step-by-step explanation:

There is a beginning amount of 180 which goes in the first bubble. Then, you divide by 3 because 1/3 is red. 180 divided by 3 is 60, so there are 60 red apples. And 180 minus 60 is 120 and that's the amount of green. Then, 1/5 of the red apples are bruised so 60 divided by 5 is 12, so 12 are bruised and sincce 60 - 12 = 48, 48 are not. And then 1/4 of the green are bruised so 120 divided by 4 is 30, which means 30 are bruised. Lastly 120 minus 30 = 90, so 90 are not bruised that are green.

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Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

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3 years ago
Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle
erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

P=2L+W+\frac{1}{2}\pi D

we have

L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}

substitute

P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)

P=20)+7+11=38\ ft

therefore

Helen will need 38 feet of fencing

Part 2)  What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

L=10\ ft\\W=7\ ft

substitute

P=2(10)+7

P=20+7=27\ ft

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

C=\frac{1}{2}\pi D

we have

D=7\ ft\\\pi =\frac{22}{7}

substitute

C=\frac{1}{2}(\frac{22}{7})(7)

C=11\ ft

therefore

The approximate distance around half of the circle is 11 feet

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Answer:

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Step-by-step explanation:

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