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3 years ago

Question is the attachment

Mathematics

1 answer:

sweet [91]3 years ago

5 0

Answer:

180

120 Green, 60 Red

^ ^

Bruised Green = 30, Not Bruised Green = 90/Bruised Red = 12, Not Bruised Red = 48

Step-by-step explanation:

There is a beginning amount of 180 which goes in the first bubble. Then, you divide by 3 because 1/3 is red. 180 divided by 3 is 60, so there are 60 red apples. And 180 minus 60 is 120 and that's the amount of green. Then, 1/5 of the red apples are bruised so 60 divided by 5 is 12, so 12 are bruised and sincce 60 - 12 = 48, 48 are not. And then 1/4 of the green are bruised so 120 divided by 4 is 30, which means 30 are bruised. Lastly 120 minus 30 = 90, so 90 are not bruised that are green.

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What is the slope of a line perpendicular to the line that passes through (4, -3) and

m_a_m_a [10]

Answer:

1/2

Step-by-step explanation:

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(4, -3)

-1 +2

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3 years ago

Danielle wants to paint her daughter's room pink. Which plan will give her paint that is the least red?

NeTakaya

Step-by-step explanation:

Plan B:

2:5 = 0.4 red to 1 white

1:4 = 0.25 red to 1 white

Students might also scale up using part-to-whole-ratios and come up with 35 parts total and 14 parts red for Plan A and 35 parts total and 7 parts red for Plan B.

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3 years ago

(PLEASE HELP FAST)

emmainna [20.7K]

Answer:

2 1/6

Step-by-step explanation:

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hope this helped

7 0

2 years ago

Read 2 more answers

Given the system of linear equations.

Degger [83]

Part(A):

To solve the system of Linear equations using Substitution:

$x+y=7 \\ 2x+y=5$

Consider the first equation, x+y=7 implies x=7-y

$\mathrm{Subsititute\:}x=7-y$

$2\left(7-y\right)+y=5$

$14-2y+y=5$

$14-y=5$

$\mathrm{Subtract\:}14\mathrm{\:from\:both\:sides}$

$14-y-14=5-14$

$-y=-9$

$\mathrm{Divide\:both\:sides\:by\:}-1$

$y=9$

$\mathrm{For\:}x=7-y$

$\mathrm{Subsititute\:}y=9$

$x=7-9=-2.$ $\mathrm{The\:solutions\:to\:the\:system\:of\:equationts\:are:}$

$y=9,\:x=-2$

PArt(B): Use a graph to verify your answer to the system:

Using Desmos graphing calculator, graph the two equations.

8 0

3 years ago

Read 2 more answers

Can someone please help? Thanks!

Paul [167]

Hey, I have already answered these all questions except the last question in your previous question. Make sure to see them.

For the last question, the answer would be the second choice as when times keep flowing, the distance still remains the same (not to be confused with speed.)

Basically when times keep going, the distance will stay the same without any changes.

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3 years ago