STEP-BY-STEP SOLUTION:
Let's first establish the inequality which we need to solve as displayed below:
y + 1 < 3
To begin with, we need to make ( y ) the subject by keeping it on the left-hand side of the inequality and placing all other numbers on the right-hand side of the equality as displayed below:
y + 1 < 3
y < 3 - 1
Then, we simply simplify / solve as displayed below:
y < 3 - 1
y < 2
ANSWER:
y < 2
Answer:
Step-by-step explanation:
(-2)(1)(3)(-1) - (1)(3)(-1)(-2)
6 - 6 = 0
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
3x cubed- 3x squared- 11x -22
Answer:
$63 when you add them both together. I don't know how to do the other part, but I know you should find the percenatge. The first is to multiply 63 * 100/1
Step-by-step explanation:
