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777dan777 [17]
4 years ago
15

Find the gradient of the line segment between the points (0,2) and (2,-8).

Mathematics
2 answers:
valkas [14]4 years ago
5 0

Answer:

Step-by-step explanation:

Paladinen [302]4 years ago
5 0

Answer:

slope = - 5

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (2, - 8)

m = \frac{-8-2}{2-0} = \frac{-10}{2} = - 5

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(K²+4)= her moms age :)
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3 years ago
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Two sides of a triangle have lengths 5 and 12. What must be true about the length of the third side?
ehidna [41]

Answer:

LESS the seventeen

Step-by-step explanation:


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Solve for x. −12x+13>35 Drag and drop a number or symbol into each box to correctly complete the solution.
Katen [24]

Answer:

x < -11/6.

Step-by-step explanation:

−12x + 13 > 35

-12x > 35 - 13

-12x > 22

Divide both sides by -12 and invert the inequality sign:

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7 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Paha777 [63]
Correct Answer:
Option A. 0.01

Solution:
This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.

Converting 90 to z-score:

z= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10}} }=2.33

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.

Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
4 0
3 years ago
The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.
djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

where,

r_1 = radius of sphere = \frac{Diamtere}{2}=\frac{8cm}{2}=4cm

r_2 = radius of cylindrical wire = \frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

\frac{4}{3}\times r_1^3=r_2^2h

\frac{4}{3}\times (4)^3=(0.1)^2h

h=8533.33cm\approx 8533cm

Therefore, the length of the wire is, 8533 cm

6 0
3 years ago
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