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MatroZZZ [7]
4 years ago
7

Can the two integers both be negative? Explain

Mathematics
1 answer:
liberstina [14]4 years ago
5 0
If you are referencing a picture, there is none attached to this post. If you can repost with a picture I can try to help you!
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Which expressions are equivalent?
olga55 [171]

Answer:

C none of the above

Step-by-step explanation:

x + z + y

is not going to be equal to x + y - z

Its like saying 10 + 5 - 4 = 11

To 10 + 5 + 4, they are not going to be equal

4 0
3 years ago
Read 2 more answers
Given the equation −4square root of x minus 3 = -12, solve for x and identify if it is an extraneous solution. x = 0, solution i
soldier1979 [14.2K]

Answer:

square root of 81

square root of 1000

square root of 34

square root of 169

Step-by-step explanation:

4 0
3 years ago
line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equat
VMariaS [17]
Slope of the line J
(6-1) / (-3-(-6))
5 / 3

so
m = 5/3

If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26

equation is
y = (5/3)x - 26
7 0
4 years ago
5) 5 ft<br> A) 38 ft<br> C) 18 ft<br> B) 15<br> D) 16 ft
Mrrafil [7]

Answer:

the answer is a

Step-by-step explanation:

3 0
3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
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