Ask question

Ask question

All categories

MA_775_DIABLO [31]

3 years ago

14

Select the correct difference. 5d 2 + 4d - 3 less 3d 2 - 2d + 4 2d2 + 2d + 1 2d2 + 6d - 7 2d2 + 6d + 7 -2d2 - 6d + 1

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

If you would like to solve (5d^2 + 4d - 3) - (3d^2 - 2d + 4), you can calculate this using the following steps:

(5d^2 + 4d - 3) - (3d^2 - 2d + 4) = 5d^2 + 4d - 3 - 3d^2 + 2d - 4 = 2d^2 + 6d - 7

The correct result would be <span>2d^2 + 6d - 7.</span>

Ulleksa [173]3 years ago

3 0

Answer:

2d^2 + 6d - 7.

Step-by-step explanation:

You might be interested in

Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose

yawa3891 [41]

Answer:

$V=5\sqrt{3}\ m^3$

Step-by-step explanation:

we know that

The volume of a trough is equal to

$V=BL$

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

$B=\frac{1}{2} b^{2} sin(60\°)$

where

$b=2\ m$

$sin(60\°)=\frac{\sqrt{3}}{2}$

substitute

$B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})$

$B=\sqrt{3}\ m^{2}$

step 2

Find the volume of a trough

$V=BL$

we have

$B=\sqrt{3}\ m^{2}$

$L=5\ m$

substitute

$V=(\sqrt{3})(5)$

$V=5\sqrt{3}\ m^3$

3 0

3 years ago

ss7ja [257]

The answer is: g= 6y+8-9/y

4 0

3 years ago

I need help in this . Just ignore that equation in top of the problem

GuDViN [60]

Communtative property

5 0

3 years ago

Read 2 more answers

What is the area of the playground shown? The edges of the playground meet at right angles, except for the edge whose length is

Dennis_Churaev [7]

Answer:

520,000

Step-by-step explanation:

1400 x 200 = 280000

(400 + 800) x 400 /2 = 240000

240000 + 280000 = 520000

3 0

2 years ago

So you may see more than one post abt these bc its due at 11:59 lol

dusya [7]

Answer:

quadrilateral

<3

Step-by-step explanation:

8 0

3 years ago