I need help on #3 I don't understand systems of linear inequalities since I wasn't there when my teacher explained it

Mathematics

1 answer:

photoshop1234 [79]3 years ago

3 0

Since y is anything greater than 2, you would draw a straight line across the point (from left to right) and if you had to shade you would shade above it (:

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I need help answering this ASAP

anyanavicka [17]

Answer:

False, this is not a function

Step-by-step explanation:

This would not represent a function

This would fail the vertical line test

One value of the input has more than one value for the output

4 0

3 years ago

How to find the asymptotes of a hyperbola?

stellarik [79]

Vertical asymptote:
Find the restriction on x. This is the easiest of the three asymptotes you will need to find (even if only two can show at a time). As a hyperbola is in the form: $\frac{1}{x}$ , you only need to find the restriction on the denominator, namely denominator can never be zero. Hence, let the denominator equal to zero to find the vertical asymptote.

Horizontal asymptote:
Find the restriction on y. To do this, you need to simplify the top and bottom to its lowest terms. If it simplifies to a form such as: $a + \frac{b}{x}$ , then the horizontal asymptote becomes y = a. You need to think to yourself, as x grows to infinite, and shrinks to negative infinite, what happens to the function? Does it slowly curve to a stop?

Oblique asymptote:
This is a pretty rare kind, but it still exists, so don't be naive to this sort of asymptote. This is a form of horizontal and vertical asymptote, only it's at an angle. That is, this asymptote is a set of x and y-coordinates that work in unison to produce a curvature or line.

Let's consider: $f(x) = \frac{x^{2} - 6x + 7}{x + 5}$

Now, in normal term, a horizontal asymptote would have a degree higher in the denominator than in the numerator. However, it's flipped in this case.

Now, you will need to long divide this set of polynomials to yield a straight y = x line, except it's been moved 11 units to the right to yield a y = x - 11 line.

Remember: these exist because the highest power is in the numerator and not the denominator.

5 0

3 years ago

2. From the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. Find the angle of depression to t

ArbitrLikvidat [17]

$34^{\circ}$ is the angle of depression from the vertical cliff.

Option: A

Step-by-step explanation:

Given that, Height of the cliff (opposite side) = 40m

Distance of object from the base of the cliff (adjecent side) = 59.3m

To find the angle of depression of the object. From trigonometric rule in a right angled triangle, we know that $\tan \theta=\frac{\text { opposite side }}{\text { adjecent side }}$ $\theta=\tan -1 \frac{\text { opposite side }}{\text { adjecent side }}$ Angle of depression = $\tan -1 \frac{\text { height of cliff }}{\text { Distance of object from the base of the cliff }}=\tan ^{-1} \frac{40}{59.3}=34^{\circ}$ Therefore, the angle of depression to the object is $34^{\circ}$ .