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VMariaS [17]
4 years ago
14

a cash register contains only five dollar and ten dollar bills. It contains twice as many five's and tens if the total amount of

money is $680 how many tens are in the cash register?
Mathematics
2 answers:
aivan3 [116]4 years ago
6 0

Answer:

There are 34 tens and 68 fives because 34*5 + 68*10 = 680.

Step-by-step explanation:

ololo11 [35]4 years ago
4 0

Answer:

There are 34 Tens and 68 Fives

Step-by-step explanation:

2X*5+X*10=680  

Multiply 2X by 5 to get 10X.

10X+X*10=680  

Multiply X by 10 to get 10X.

10X+10X=680  

Since 10X and 10X are like terms, add 10X to 10X to get 20X.

20X=680  

Divide each term in the equation by 20.

(20X)/(20)=(680)/(20)  

Simplify the left-hand side of the equation by canceling the common factors.

X=(680)/(20)  

Simplify the right-hand side of the equation by simplifying each term.

X=34 tens

68 fives

Prove:  

34*10= 340

68*5= 340

340+340=680

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Answer:

It would take 4 men 37 hrs and 12 mins to complete the same task.

step-by-step explanation:

Let X be the time the four men would use to complete the task.

From the question, 6 men completed a task in 24 hrs and 48 mins

But

24 \: hrs \: 48 \: mins = 24(60mins) + 48 \: mins=1488 \: mins

Using ratio and proportion

6 \: men:1488 \: mins

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4 men required more time to complete the task

Hence:

x =  \frac{6}{4} \times 1488 \: mins

x = 2232 \: mins

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Step-by-step explanation

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Solve the system of equations using substitution<br> 4x + 2y = 16<br> =−12+5
mario62 [17]

Answer:

x=\frac{70}{11},\:y=\frac{20}{11}

Step-by-step explanation:

\begin{bmatrix}4x+2y=16y\\ y=-\frac{1}{2}x+5\end{bmatrix}

\mathrm{Substitute\:}y=-\frac{1}{2}x+5

\begin{bmatrix}4x+2\left(-\frac{1}{2}x+5\right)=16\left(-\frac{1}{2}x+5\right)\end{bmatrix}

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\begin{bmatrix}3x+10=16\left(-\frac{1}{2}x+5\right)\end{bmatrix}

Isolate x for 3x+10=16(-1/2x+5): x=\frac{70}{11}

\mathrm{For\:}y=-\frac{1}{2}x+5

\mathrm{Substitute\:}x=\frac{70}{11}

y=-\frac{1}{2}\cdot \frac{70}{11}+5

-\frac{1}{2}*\frac{70}{11}+5=\frac{20}{11}

y=\frac{20}{11}

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=\frac{70}{11},\:y=\frac{20}{11}

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