The confidence interval for the proportion of students attending a football game is [0.6592, 0.7044].
Confidence interval can be calculated by below formula

where the left part is the lower interval and right side is the higher interval.
Pcap = 750/1100
Pcap = 0.6818
Again to calculate
, as we know that the level of confidence is 90 percent so its value will be 1.645
now putting the values on the both side we can get ,
0.6818 - 1.645 x 0.014 < p < 0.6818 + 1.645 x 0.014
0.6818 - 0.023 < p < 0.6818 + 0.023
0.6588 < p < 0.7048
the nearest value is [0.6592, 0.7044]
Hence the confidence interval for the proportion of students attending a football game is [0.6592, 0.7044]
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Answer:
Directrix equation: y = 11/2
y = k - c = 6 - 1/2 = 11/2
Step-by-step explanation:
y=(1/2) x^2+6x+24
factor this
y = (1/2)* [ x^2 + 12x ] + 24
y = (1/2)* [ x^2 + 12x + 36 - 36] + 24
y = (1/2)* [ (x + 6)^2 - 36] + 24
y = (1/2)* (x + 6)^2 - 18 + 24
y = (1/2)* (x + 6)^2 + 6
y - 6 = (1/2)* (x + 6)^2
2*(y - 6) = (x + 6)^2
4c = 2, (h, k) = (-6, 6)
c = 1/2
Directrix equation: y = k - c = 6 - 1/2 = 11/2
1 a)
6^2*6^3= 6^(2+3)=6^5
1b)
(-2)^2 *(-2)^4 = (-2)^(2+4)= (-2)^6=2^6
1c
Answer:
(0.46, 0.52)
Step-by-step explanation:
The formula for Confidence Interval with Proportion
CI = p ± z × √p(1 - p)/n
Where
p = Proportion = x/n
x = 346
n = 706
p = 346/706
p = 0.49
z = z score of Confidence Interval 90% = 1.645
Therefore:
CI = 0.49 ± 1.645 × √0.49(1 - 0.49)/706
CI = 0.49 ± 1.645 × √0.49 × 0.51/706
CI = 0.49 ± 1.645 × 0.0188139843
CI = 0.49 ± 0.0309490042
Hence:
Confidence Interval is
0.49 - 0.0309490042
= 0.4590509958
≈ 0.46
0.49 + 0.0309490042
= 0.5209490042
≈ 0.52
Therefore , the confidence interval of the population proportion is
(0.46, 0.52)