Find the distance between the points (1,3) and (5,0).
1 answer:
distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2
I.e,[{5-1)^2+(0-3)^2]^1/2
[16+9]^1/2
[25]^1/2
5
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12 beacause it is what it is jk im just put anything fr the challenges plz rate me 5 stars
Answer: multiple the length vu the width
Step-by-step explanation:
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Arc length = central angle/360.2pi.r
7/3pi=?/360.2pi.6
?=7.10
?=70
Answer:
r = 1
Step-by-step explanation:
we know that :

Then

Then

Then
5×12 = 4×(16-r)
Then
60 = 64 - 4r
Then
4r = 64 - 60
Then
4r = 4
Then
r = 1