Answer:
Total derangement = 4
Step-by-step explanation:
To find - How many derangement of {1, 2, 3, 4, 5, 6} begin with the integers 1, 2, and 3, in some order?
Solution -
Given that,
The first three numbers are 1, 2, 3
The only derangement possible are - 231 and 312
Now,
The remaining elements 4, 5, 6 are the 4th, 5th and 6th number in the derangement
Now,
In order for the permutation of the derangement, the only possibility for 123 are 564 and 645
∴ we get
The Total derangement are -
231564
231645
312564
312645
So,
Total derangement = 4
Answer:
(- 2, 4 )
Step-by-step explanation:
A translation of 5 units left means subtract 5 from the original x- coordinate.
A translation of 6 units up means add 6 to the original y- coordinate.
Thus
(3, - 2 ) → (3- 5, - 2 + 6 ) → (- 2, 4 )
Answer:
Imaginary numbers.
Step-by-step explanation:
Not sure quite what the question is asking, but negative square roots will give an answer in terms of 'i' - which is an imaginary number.
Answer:
A
Step-by-step explanation:
Cause it right and pls dont remind me
