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sashaice [31]
3 years ago
7

99 POINTS .Use the parabola tool to graph the quadratic function f(x)=2x2+16x+30 . Graph the parabola by first plotting its vert

ex and then plotting a second point on the parabola. right answer gets brainliest.

Mathematics
2 answers:
Iteru [2.4K]3 years ago
6 0
Hello!

We can put in numbers for x to get points of the graph

2(-4)^2 + 16(-4) + 30 = -2

One point is (-4, -2)

2(-3)^2 + 16(-3) + 30 = 0

The next point is (-3, 0)

2(-5)^2 + 16(-5) + 30 = 0

The third point is (-5, 0)

The parabola has a vertex of (-4, -2) and goes through the points (-3, 0) and (-5, 0)

Hope this helps!
andre [41]3 years ago
3 0
F(x)=2x²+16x+30=2(x²+8x)+30=2(x²+2*4x+16)+30-32=2(x+4)²-2
Vertex(-4,-2)
Another point, for example x-int.
2x²+16x+30 =0
2(x²+8x+15)=0
x²+8x+15=0
(x+3)(x+5)=0
x=-3, x=-5
You can take (-3,0) or (-5,0)

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<h3>Equation</h3>

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