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HACTEHA [7]
3 years ago
13

A model car has a list price of $46.20. the model is on a sale at 15% off. find the total cost to the nearest cent after a 4.5%

tax added to the sales tax
Mathematics
1 answer:
katrin [286]3 years ago
6 0
The total cost is $41.04
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A 6 sided cube with sides labeled 1,2,3,4,5 and 6 is rolled 50 times. What is a good prediction for the number of times 5 will b
Liono4ka [1.6K]

Answer:

A good prediction is that the number 5 will be rolled 8 times

Step-by-step explanation:

Here, we want to get the number of times 5 would occur in a roll of 50

firstly, we need the probability of having a 5 come up

To do this, we have to divide the number of 5’s by the count of possible numbers

We have this simply as 1/6

Now, we have to multiply this by 50

we have this as;

1/6 * 50 = 8.333

This is approximately 8

so we have it that in 50 rolls, we can have the number 5 coming up 8 times

7 0
3 years ago
4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reac
alexandr1967 [171]

Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have

100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂

Hydrogen (H) has a molar mass of about 1.008 g/mol, so

100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂

In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have

3.570 • 3 ≈ 10.71

so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.

(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.

(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.

(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or

7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃

8 0
3 years ago
A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

so that the left side condenses into the derivative of a product,

\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
23. What is the largest prime factor of 225?<br>A.<br>3<br>B.<br>5<br>C.<br>15<br>D.<br>17.​
ruslelena [56]

Answer:

15

Step-by-step explanation:

because 15 times 15 equals 225

6 0
4 years ago
Read 2 more answers
X =<br><br><br>A.1<br><br>B.3<br><br>C.7<br><br>Picture Provided Below
Yakvenalex [24]

Answer:

B 3

Step-by-step explanation:

We can use the secant-secant formula:

(whole secant) x (external part) = (whole secant) x (external part)

9 * 4 = 12 *x

36 = 12x

Divide each side by 12

36/12 =12x/12

3 =x

7 0
3 years ago
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