Answer:
The answer to your question is car 1 = 30 gal and car 1 = 20 gal
Step-by-step explanation:
car 1 = a
car 2 = b
Efficiency of car 1 = 35 mi/gal
Efficiency for car 2 = 20 mi/gal
Total distance = 1450
Total gas consumption = 50 gal
Equations
35a + 20b = 1450 ------- (I)
a + b = 50 ------- (II)
Solve by elimination
Multiply equation II by -35
35a + 20b = 1450
-35a - 35b = -1750
Simplify
0 - 15b = -300
Solve for b
b = -300/-15
Result
b = 20
Substitute b in equation II to find a
a + 20 = 50
Solve for a
a = 50 -20
Result
a = 30
Answer: C) 50
Step-by-step explanation:
The smallest number on the plot is 43. The largest is 93. The range of a chart is the largest number - the smallest number. Thus, simply do 93-43 to get 50.
Hope it helps <3
<span>the equation -2x² + 5x -3=0, we notice that the sum of the coefficient equals 0, -2+5-3=0, if such a case happens, the solution of the previous equation will be, x=1 (always) and x= c/a, a=-2, and c=-3, so x=-3/-2, finally, the answer is: the 2 in the denominator should be -2</span>
Answer:
x = 2
Step-by-step explanation:
Multiply both sides by (x-5) and expand:
(x+4)/(x-5)*(x-5) = -2(x-5)
x+4 = -2x+10
Subtract 4 from both sides:
x+4-4 = -2x+10-4
x = -2x+6
Add 2x to both sides:
x+2x = -2x+6+2x
3x = 6
Divide both sides by 3:
3x/3 = 6/3
x = 2
Answer:
The probability is 0.683
Step-by-step explanation:
To calculate this, we shall be needing to calculate the z-scores of both temperatures
mathematically;
z-score = (x-mean)/SD
From the question mean = 78 and SD = 5
For 73
z-score = (73-78)/5 = -5/5 = -1
For 83
z-score = (83-78)/5 = 5/5 = 1
So the probability we want to calculate is within the following range of z-scores;
P(-1 <z <1 )
Mathematically, this is same as ;
P(z<1) - P(z<-1)
Using the normal distribution table;
P(-1<z<1) = 0.68269 which is approximately 0.683