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8090 [49]
3 years ago
11

Which of the following equations could be used to solve the given equation?

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
If we simplify like terms on left and right sides we gwt

16x + 9 =  4x

Its B
dmitriy555 [2]3 years ago
5 0

Answer:  The correct option is (B) 16x+9=4x.

Step-by-step explanation:  We are given to select the correct equation that could be used to solve the following equation :

9x+26+7x-17=2x+(-3x)+5x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the correct equation, we need to simplify the given equation (i).

From equation (i), we get

9x+26+7x-17=2x+(-3x)+5x\\\\\Rightarrow (9+7)x+(26-17)=2x-3x+5x\\\\\Rightarrow 16x+9=(2-3+5)x\\\\\Rightarrow 16x+9=4x.

Thus, the required equation is 16x+9=4x.

Option (B) is CORRECT.

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I think you are correct actually.

6 0
4 years ago
Mr.wayne repeat his tie every 12 days and mr pickett repeats his tie every 10 days.what day will they wear the same tie
4vir4ik [10]
The answer would be day number 60
4 0
3 years ago
When is the best time to use square roots to solve a quadratic? Choose the one BEST
blondinia [14]

Answer: D, When the constants are perfect squares.

Step-by-step explanation:

the “best” method whenever the quadratic equation only contains x2 terms. That implies no presence of any x term being raised to the first power somewhere in the equation.

Hopefully this helps!

8 0
3 years ago
(Picture provided)<br><br> Helppppppp plsss
denpristay [2]

Answer:

100 degrees

Step-by-step explanation:

at first i thought it was a right angle but i looked at the other shape and seen it was a 80 degree angle for B, then i seen C on the same shape, so that just proved what i thought that W was on the other shape because its not a 90 degree right angle, its a bigger angle not as big as C on the other shape, but not a 90 degree angle either, so its 100 degree angle.

3 0
3 years ago
I need help with this math question
ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}

Step 2: Place a logarithm base 7 on both sides

7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}

Step 3: Solve for x

\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5

Neat exponent question :)

7 0
2 years ago
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