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3 years ago

Use the quadratic formula to solve x² + 9x + 10 = 0.

Mathematics

2 answers:

valentina_108 [34]3 years ago

7 0

C.x=-7.7 and x=-1.3 should be the answer

maxonik [38]3 years ago

6 0

C SOULD BE THE RIGHT ANSWER

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Find the value of x that makes A||B <2= 2x+10 <4=4x+80

lawyer [7]

Answer:

Step-by-step explanation:

this is the correct answer

8 0

2 years ago

What is the measure of

Kamila [148]

Answer:

64.4

Step-by-step explanation:

In one of the trig formulas, it states sin <a/A = sin<b/B = sin<c/C

So we have in this case:

sin(70)/12 = sin x/14 Note: x is just a variable for the angle <ABC

14(sin70)/12 = sin x

sin^-1(14(sin70)/12) = x

x=64.4

Your welcome, and comment if you have any questions! :D

6 0

2 years ago

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x

Greeley [361]

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

$2^x=1-3^x$

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

$2^{-0.75}=1-3^{-0.75}$

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

$2^{-1.25}=1-3^{-1.25}$

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

$2^{0.75}=1-3^{0.75}$

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

$2^{1.25}=1-3^{1.25}$

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

6 0

3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

3 years ago

What is the slope of the line that passes through (-2, 5) and (3, 9)?

Naya [18.7K]

Answer: 4/5

Step-by-step explanation:

1. you need to know the formula which is m = y2-y1/x2-x1

2. you plug in the numbers which would be 9-5/3-(-2)

3. you get your answer as 4/5

4. the answer is 4/5

3 0

3 years ago

Read 2 more answers