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torisob [31]
3 years ago
11

150,75,50 what number comes next

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

35 or 25

Step-by-step explanation:

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Floyd is an aspiring music artist. He has a record contract that pays him a base rate of \$200$200dollar sign, 200 a month and a
Thepotemich [5.8K]
Floyd's contract consists of
(i) $200 per month fixed.
(i) $12 per album sold.

Let x =  number of albums sold last month.
Because total earnings is $644, therefore
200 + 12x = 644

To find x, do the following:
Subtract 200 from each side.
12x = 644 - 200 = 444
Divide each side by 12.
x = 444/12 = 37

Answer:
The equation is 12x + 200 = 644.
The solution for x (number of albums sold) is 37.

5 0
3 years ago
A group of 29 friends get together to play a sport first person must be divided into team each team has to have exactly 4 player
telo118 [61]

Answer:

7 teams remaining a person

Step-by-step explanation:

29/4 = 7 remainder 1

5 0
3 years ago
Select the equation written in slope-intercept form that corresponds to the given slope and y-intercept. The linear equation whe
ehidna [41]

Answer:

Step-by-step explanation:

hello :

y=mx+b

The linear equation when m = –6 and b = 1  is : y=-6x+1

The linear equation when m = 6 and b = -2  is : y=6x-2

The linear equation when m = 1 and b = 6  is : y=x+6

6 0
3 years ago
Read 2 more answers
-5x=5 solve for x plssss help
KengaRu [80]

Answer:

x=-1

Step-by-step explanation:

-5x=5

-x=1

x=-1

or solve this way

-5x=5

5x=-5

x=-1

4 0
3 years ago
Read 2 more answers
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
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