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hram777 [196]
3 years ago
5

Simplify 3 (x+2y) +5x (-y+7)​

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

3(x+2y)+5x(7-y)

= 3x + 6y + 35x - 5xy

= 38x-5xy+6y

Hope this helps!

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You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel
erica [24]

Answer:

a)

P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357

P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034

P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377

P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015

P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

100 welders, so N = 100

Sample of 15, so n = 15

In total, 5 defective, so k = 5

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357

P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034

P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377

P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015

P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

(b) Determine the probability that there are at least 4 defective welders in the sample?

P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154

0.154% probability that there are at least 4 defective welders in the sample

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<span>A study found that in a certain region housing prices had decreased by half over a ten year period. A dollar bill is used to depict the initial average cost of a home in this region. A second dollar bill to depict the average housing price at the end of the ten year period should be <em>ONE-FOURTH</em> the <em>AREA</em> of the original bill. </span><span />
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The perimeter would be 13x/2+6

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A number w decreased by 10 is 3.​
katrin [286]

Hello from MrBillDoesMath!

Answer:

13

Discussion:

w - 10 = 3               => add 10 to both sides

w = 3 + 10

w = 13

Thank you,

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The answer is -15. Make sure to friend me and thank me
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