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sashaice [31]
3 years ago
7

D" id="TexFormula1" title="\frac{x^{2} }{3x^{2}+8x-3 } divided \frac{x-3}{x+2}" alt="\frac{x^{2} }{3x^{2}+8x-3 } divided \frac{x-3}{x+2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

ddsdvffgdf gddccd fddf

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Answer:

Due to the location of the marker, it is closest to:
C.) 10/16 = 5/8 lb.


Each pound is divided into 16ths since 10 sixths are represented by the marker then the answer would be 10/16.

10 / 16 = 5 / 8


10 divided by 2 = 5
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16 divided by 2 = 8


Therefore 10 / 16 = 5 / 8.


Step-by-step explanation:

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Please check the explanation.

Step-by-step explanation:

<u>Calculating the area of the outer rectangle:</u>

Given

  • The length outer rectangle = l = 3x - 1
  • The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

A = wl

    = (5x + 2) (3x - 1)

    =5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)

     =5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1

      =15x^2+x-2

<u>Calculating the area of the inner rectangle:</u>

Given

  • The length inner rectangle = l = x + 7
  • The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

   = x(x+7)

   = x² + 7

<u>Calculating the area of the shaded region:</u>

As

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

  • The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

                                  = 15x² + x - 2 - (x² + 7)

                                   =  15x² + x - 2 - x² - 7

                                   = 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

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