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allochka39001 [22]
3 years ago
14

Find the midpoint of the segment with the following endpoints. (-9, -5) and (-1, -9)

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

The answer is

<h2>( - 5 \: , \:  - 7)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-9, -5) and (-1, -9)

The midpoint M is

<h3>M = ( \frac{ - 9 - 1}{2}  , \:  \frac{ - 5 - 9}{2} ) \\  = ( -  \frac{10}{2} , \:  -  \frac{14}{2} )</h3>

We have the final answer as

<h3>( - 5 \: , \:  - 7)</h3>

Hope this helps you

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7 0
3 years ago
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Which of the following could be the ratio between the lengths of the two legs
skad [1K]

9514 1404 393

Answer:

  B, E

Step-by-step explanation:

The ratios of side lengths in a 30-60-90 triangle are ...

  1 : √3 : 2

The two legs are the shorter sides, so any ratio that reduces to 1 : √3 is an appropriate choice:

  B.  1 : √3

  E.  2√3 : 6

3 0
3 years ago
I have corner points of:
WARRIOR [948]
The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10

So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)

Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z

------------------

Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later. 
So let's call it A. Let A = 25

Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later

Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later

Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727

------------------

In summary, we found
A = 25
B = 21
C = 39
D = 22.2727

The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)

Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)

------------------

Final Answer: 39

7 0
3 years ago
one tank is filling at a rate of 3/4 per gallon per 2/3 minute .a second tank is at a 5/8 gallon per 1 half gallon per 1/2 minut
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recall\ that\implies \cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\qquad thus&#10;\\ \quad \\&#10;&#10;\cfrac{\frac{3g}{4}}{\frac{2m}{3}}\implies \cfrac{3g}{4}\cdot \cfrac{3}{2m}\implies \cfrac{\square ?}{\square ?}&#10;\\-------------\\&#10;\cfrac{\frac{5g}{8}}{\frac{1m}{2}}\implies \cfrac{5g}{8}\cdot \cfrac{2}{1m}\implies \cfrac{\square ?}{\square ?}

so... you tells us, which filling rate is the bigger and thus faster one?

6 0
3 years ago
Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5
emmasim [6.3K]
Answer:\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}Explanation:

The given addition exercise is:

\frac{2}{5}+\frac{1}{3}

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}

Multiply 1/3 by 5/5

\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}

The addition becomes

\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

Therefore, we can fill in the vacant boxes as shown below:

\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

4 0
1 year ago
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