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Ne4ueva [31]
3 years ago
15

A function that is defined by using different functions over subsets of the domain.

Mathematics
1 answer:
Katen [24]3 years ago
8 0

Answer: Solution

Step-by-step explanation:  I believe the answer is solution

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Which is the function represented by the table
mestny [16]

Answer:

the first function is correct

8 0
4 years ago
W
elixir [45]

Answer:

1st Question Answer: y = -2x-3=

x=−1/2 y+ −3/2

2nd Question y = 2x - 1

Answer: x=1/2y+1/2

3rd Question : y = x + 4

Answer: x=y−4

4th Question: YX+2

Answer: xy+2

5th Question:y = -2x - 3

Answer: -2x - 3

6th Question: y = x +4

Answer: x=y−4

7th Question: y = 2x-1

Answer: x=1/2y+1/2

8th Question:y = -x + 2

Answer: x=−y+2

Step-by-step explanation:

Hope this helps :)

PLS BRAINLIEST I TOOK LONG TO COMPLETE THIS

6 0
3 years ago
What is the answer to Write two phrases for the expression 13p? Multiple choice question. Either the product of 13 and p;13 mult
castortr0y [4]

Answer:

solve the equation for the variable. Then plug that variable value into the expression and simplify to get the answer.

Step-by-step explanation:

6 0
2 years ago
Evaluate ( 75 − 3/17 + 1 ) 2
Ede4ka [16]

Answer:

2=1289/17

Step-by-step explanation:

use the given functions to set up and simplify 2

7 0
2 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
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