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3 years ago

Y= -1/3x+2

1 answer:

8 0

Plugging x in, we have -x/3+2, which is -2/3+2=1.3 (with the 3 repeating).

To graph it, try desmos.com if you need help :)

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A new restaurant with 134 seats is being planned. Studies show that 62% of the customers demand a smoke-free area. How many se

zzz [600]

Answer: 100

Step-by-step explanation:

Given : The total number of seats planned in new restaurant =134

The percentage of customers demand a smoke-free area = 62%

It can also be written as $62\%=\dfrac{62}{100}=0.62$

The mean of this binomial distribution will be :-

$\mu=np\\\\\mu=(134)(0.62)=83.08$

Standard deviation:-

$\sigma=\sqrt{np(1-p)}\\\\\Rightarrow\sigma=\sqrt{134(0.62)(0.38)}\approx5.6$

Now, the number of seats should be in the non-smoking area in order to be very sure of having enough seating there :-

$\mu+3\sigma=83.08+3(5.6)=99.88\approx100$

4 0

3 years ago

Devonte used the change of base formula to approximate log Subscript 8 Baseline 25. Which expression did Devonte use?.

scZoUnD [109]

Answer:

I think I did this. I think the answer choices are:

Log StartFraction 8 Over 25 EndFraction

StartFraction log 8 Over log 25 EndFraction

log StartFraction 25 Over 8 EndFraction

----> StartFraction log 25 Over log 8 EndFraction

So the answer is D

Step-by-step explanation:

6 0

2 years ago

Help me??? Please it’s urgent

Elodia [21]

The answer is option 2.

8 0

3 years ago

Read 2 more answers

Y=1/2x+1 and 2y-x=2 the system shown has how many solutions

iren [92.7K]

The answer to the question

6 0

3 years ago

A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular

Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

$m\angle AOM =30^o$

In the right triangle OAM

$tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}$

$\frac{a}{2r}=\frac{\sqrt{3}}{3}$

we have

$r=3\ units$

substitute

$\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units$

Find the area of six equilateral triangles

$A=6[\frac{1}{2}(r)(a)]$

simplify

$A=3(r)(a)$

we have

$r=3\ units\\a=2\sqrt{3}\ units$

substitute

$A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2$

Therefore

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

6 0

3 years ago