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Fofino [41]
3 years ago
5

. Tonya compared prices of two auto-rental agencies for the use of a mid-size car for one week. Affordable Auto charges 20 cents

per mile plus a flat fee of $382. Budget Auto charges 25 cents per mile plus a flat fee of $356. Which equation should Tonya use to determine the distance in miles, x , that would make the total charges of both auto-rental agencies equal?
Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

Answer:

idk

Step-by-step explanation:

nordsb [41]3 years ago
4 0

Answer:

D

Step-by-step explanation:

382 + .20m = 356 + .25m

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An area of 4 square yards is equal to 36 square feet. 10 square yards is equal to how many square feet? sq feet
lora16 [44]

Answer: 90 square feet

Step-by-step explanation:

5 0
3 years ago
What is the average of the four smallest of integers ?
Elanso [62]
This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.

 
6 0
3 years ago
(NO FILES OR LINKS OR RANDOM WORDS)
ehidna [41]

Answer:

Randomly selecting a six of diamonds - 1 / 52

Randomly selecting a 7, 8, 9 or 10 - 4 / 13

Step-by-step explanation:

There is only 1 six of diamonds in a standard deck of cards. There are 52 cards in a deck, thus the probability of pulling a six of diamonds is 1 in 52.

There are 4 of each card in a deck. so they are 4 7's, 4 8's. 4 9's and 4 10's. And there are a total of 52 cards in a deck. So the probability of pulling a 7,8,9 or 10 are 4 + 4 + 4 + 4 in 52

4 + 4 + 4 + 4 = 16

16 / 52 simplified is 4 / 13 Therefore the is a 4 in 13 chance of pulling a 7 8 9 or 10

The other ones are correct

3 0
3 years ago
Find x. Round to the nearest tenth.
Lyrx [107]

Answer:

55 = 550

Step-by-step explanation:

5 0
3 years ago
Remember to check for extraneous solutions
larisa86 [58]

Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}

3 0
3 years ago
Read 2 more answers
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