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sergejj [24]
3 years ago
6

Write these expressions in exponential form:

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0

1. 10^5

2. z^5*x^3*y^2

3. 1

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A surveyor standing at A notices two posts B and C on the opposite side of a canal. The posts are 120m apart. If the angle of si
AveGali [126]

Unfortunately there isn't enough information.

Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.

5 0
2 years ago
jen wants to tile the floor of her kitchen. The floor is rectangular and measures 12 feet by 8 feet. if it costs $2.50 per squar
alexgriva [62]
Answer:

$240

Explanation:

12 × 8 = 96 _________ area in square feet

96 × 2.50 = 240 _________ in dollars

6 0
3 years ago
In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion
lys-0071 [83]

\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

<u>It's 90</u>

6 0
3 years ago
Which expresión represents, five times the quotient of two numbers?
MAXImum [283]
Let the numbers be m and n.  Then "<span>five times the quotient of two numbers" would be 5m/n.

</span>
6 0
3 years ago
A.Find the measures of the remaining angles of parallelogram KLMN. Justify each of the measures with a theorem.
Inga [223]

a.

<K = <M = 50 ...Opposite angels are congruent

<K + <L  = 180...Consecutive angles are supplementary

 50 + <L  = 180 so <L = 180 - 50 = 130

<L = <N = 130...Opposite angels are congruent

50 + <N  = 180 so <N = 180 - 50 = 130

b.

MN = LK = 7...Opposite sides are congruent

KN = LM = 10...Opposite sides are congruent

4 0
3 years ago
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