All categories

3 years ago

Write these expressions in exponential form:

Mathematics

1 answer:

Crazy boy [7]3 years ago

3 0

1. 10^5

2. z^5*x^3*y^2

3. 1

You might be interested in

A surveyor standing at A notices two posts B and C on the opposite side of a canal. The posts are 120m apart. If the angle of si

AveGali [126]

Unfortunately there isn't enough information.

Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.

5 0

2 years ago

jen wants to tile the floor of her kitchen. The floor is rectangular and measures 12 feet by 8 feet. if it costs $2.50 per squar

alexgriva [62]

Answer:

$240

Explanation:

12 × 8 = 96 _________ area in square feet

96 × 2.50 = 240 _________ in dollars

6 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago

Which expresión represents, five times the quotient of two numbers?

MAXImum [283]

Let the numbers be m and n. Then "five times the quotient of two numbers" would be 5m/n.

6 0

3 years ago

A.Find the measures of the remaining angles of parallelogram KLMN. Justify each of the measures with a theorem.

Inga [223]

<K = <M = 50 ...Opposite angels are congruent

<K + <L = 180...Consecutive angles are supplementary

50 + <L = 180 so <L = 180 - 50 = 130

<L = <N = 130...Opposite angels are congruent

50 + <N = 180 so <N = 180 - 50 = 130

MN = LK = 7...Opposite sides are congruent

KN = LM = 10...Opposite sides are congruent

4 0

3 years ago