If the side length is greater than 11.11 cm then it will not overflow.
Otherwise, it will overflow.
If Joe tips the bucket of water in a cuboid container and the water is not overflowing then the cuboid container must be of volume greater than 1370 cm³.
We find the cube root of 1370 cm³.
![\sqrt[3]{1370} \approx11.11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1370%7D%20%5Capprox11.11)
Then the cuboid container should have a side of length greater than 11.11 cm.
Here the statement "If I tip my bucket of water in the cuboid container, it will never overflow" is correct or wrong based on the information that the container has a side length lesser or greater than 11.11 cm.
If the side length is greater than 11.11 cm then it will not overflow.
Otherwise, it will overflow.
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Answer:
16
Step-by-step explanation:
like just pay attenction in class
Answer:
First we will split trapezium on two geometric figure.
One is rectangle and the second is right triangle.
When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.
We will use Pythagorean theorem to find the second cathetus b
b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>
AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm
AC=18.1cm
Good luck!!
Answer:
1/4 <u>divided by</u> 1/3
1/3 <u>divided into</u> 1/4
<u>How many</u> 1/3 <u>are in</u> 1/4
Step-by-step explanation:
Answer:
<u>Translate K to N and reflect across the line containing JK. </u>
Step-by-step explanation:
The rest of the question is the attached figure.
From the figure, we can deduce the following:
∠K = ∠N
JK = MN
HK = LN
So, N will be the image of K
By translating K to N, The segment JK will over-lap the segment MN,
Then, we need to reflect the point H across the the line containing JK to get the point L
So, the translation and a reflection that will be used to map ΔHJK to ΔLMN:
<u>Translate K to N and reflect across the line containing JK. </u>
